(-0.04x^2)-x+50=0

Solution for (-0.04x^2)-x+50=0 equation:

(-0.04x^2)-x+50=0

We add all the numbers together, and all the variables

(-0.04x^2)-1x+50=0

We get rid of parentheses

-0.04x^2-1x+50=0

a = -0.04; b = -1; c = +50;
Δ = b2-4ac
Δ = -12-4·(-0.04)·50
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3}{2*-0.04}=\frac{-2}{-0.08}
=+25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3}{2*-0.04}=\frac{4}{-0.08}
=-50
$